In 8086 real mode addressing the 16 bit segment register is added with 16 bit offset and 20 bit address is generated. Eg: Case 1: ******** Segment Reg: B230 Offset Reg: 2052
Now the resulting 20 bit address is generated as Segment reg+ B230+ offset 02052 ------------------ Address = B4352 The resulting address generated is accessed.
Case 2 ****** Now my doubt is what if Segment Register: FFFF and offset register: FFFF value in it.If we calculate the Resulting 20 bit address it will cause an overflow Right!!!! Can somebody clarify how 20 bit address is generated in this case?????
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